1 - compare 4 with 4& W: p7 x! s" c; }
if (4v4)= same that means the rest of 4 is got more weight
, ~8 X, u6 ?# Z! S8 vTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。 then goto 2 - compare rest of(4) - 2 with 2
* z6 }: Z8 k8 n: A5.39.217.77 if (left side is more weight)tvb now,tvbnow,bttvb( P& W% `4 g: [$ ]: b
then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
* ?' z1 U: ]% g, W3 Ltvb now,tvbnow,bttvb else ( right side is more weight)
# O% u: |5 W+ w% {! @! ATVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。 then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
9 H& a! z6 U d$ s+ uelse ( the left 4) then compare with above , or right 4 also can compare above method... |
發表於 2010-9-21 10:33 PM
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