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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
' ~  x; F# C7 D& X0 o将比较重的那份再平均分成两份成一次
  z  |+ Y  W- D3 O/ P: Y7 Ttvb now,tvbnow,bttvb剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 45.39.217.77) b! S0 K3 S$ ?! x- |
if  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇0 C8 y: k2 x) h- j: K! S7 G" z
    then goto 2 - compare rest of(4)  - 2 with 2
. ?0 c6 F5 p' b           if (left side is more weight)tvb now,tvbnow,bttvb3 \1 K$ [9 H! D- k' I  R* b: Z
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer" k' {: i% {. O0 p% T
          else ( right side is more weight)5.39.217.77" Y/ [; K6 {5 ?; n# T* n
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
- [' T) W# l' {  K0 Oelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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