zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
  ?5 T+ s$ X, t4 u  ~# n/ _9 k5 Utvb now,tvbnow,bttvb将比较重的那份再平均分成两份成一次: S7 c7 D' X; K* Y- O& X
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 45.39.217.77( g' p$ J! Z) G4 L9 [" J
if  (4v4)= same that means the rest of 4 is got more weight5.39.217.77/ v0 J* s+ L# i% O
    then goto 2 - compare rest of(4)  - 2 with 2 5.39.217.77$ g: q# G: T1 z; P0 g
           if (left side is more weight)5.39.217.77$ `1 N2 P& U8 z3 Z* {
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer公仔箱論壇& O4 P. B5 D6 B% _' ~+ ?% E" `
          else ( right side is more weight)tvb now,tvbnow,bttvb, Z" T9 U" G  _5 H  O. P# g
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
3 S- [- _, N) w& }" F# ]+ ]* N; ttvb now,tvbnow,bttvbelse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。