zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
- ~$ k/ D* A" x: K/ ?将比较重的那份再平均分成两份成一次公仔箱論壇8 }# ^! ~6 G4 H, h& W0 E
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4公仔箱論壇- J( Q! x% S3 r  V! v) j9 N
if  (4v4)= same that means the rest of 4 is got more weighttvb now,tvbnow,bttvb$ N4 W9 M) Q% ^# r6 P
    then goto 2 - compare rest of(4)  - 2 with 2 5.39.217.779 r7 v5 s% j, ~2 `! z' t
           if (left side is more weight)tvb now,tvbnow,bttvb2 J: {" }' D0 a- Y- L
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
: ^# T% _+ `7 a/ q  j; o% J          else ( right side is more weight)公仔箱論壇+ W. M% V5 a% v2 o  ^7 v. D5 v
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.77' B* a2 n, Z$ f# }; A, X
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。