zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次0 H, ?& C$ {6 t
将比较重的那份再平均分成两份成一次公仔箱論壇6 t5 W1 z4 y- m
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
% i. W" ^; \- j) K7 E) q3 E公仔箱論壇if  (4v4)= same that means the rest of 4 is got more weight
$ e* D2 [! T( ^& G; c# m8 rTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。    then goto 2 - compare rest of(4)  - 2 with 2 公仔箱論壇- f' }3 q+ J- Z% \5 S5 h
           if (left side is more weight)5.39.217.777 X* u- y# |4 B+ }3 z
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
  U0 r% {# t: ~# o- h# e4 T公仔箱論壇          else ( right side is more weight)/ m' \( l8 Z4 _9 y
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.77$ b, T7 d  n. ^  e% r; d, \
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。