1st round 6 each size, take 6 of the ping pong from the side with various..) z( |6 r: [5 N# ]/ w% e
2nd round 3 each size which are those ping pong from the various side.. n den same thing..
: q' w1 r0 O- P+ f/ l. D1 j( A3rd round weight 2 of the 3 ping pong... + ^0 r+ H$ ~7 h" M$ m( {
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n den observe..5.39.217.779 m! }; a# Z# ~: @! W2 x
if the 2 weighted ping pong have nth wrong, den the 1 with weird weight is the left over 1 5.39.217.777 o7 k% A& ~ o3 y- k
otherwise it would be the 1 on the side with various.. |
發表於 2010-1-25 07:25 PM
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發表於 2010-2-4 02:56 AM
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