1st round 6 each size, take 6 of the ping pong from the side with various..( w0 P0 F/ Z5 J! c7 {
2nd round 3 each size which are those ping pong from the various side.. n den same thing..
! T& ]" U* p+ ?: R1 K1 X3rd round weight 2 of the 3 ping pong... 6 b5 a$ {* S% x A) [$ `, b# o
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n den observe..+ j" k4 ]2 m( [' B5 l1 u# k2 u1 G6 W
if the 2 weighted ping pong have nth wrong, den the 1 with weird weight is the left over 1
5 x9 S; L7 H; c/ Q2 J5.39.217.77otherwise it would be the 1 on the side with various.. |
發表於 2010-1-25 07:25 PM
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發表於 2010-2-4 02:56 AM
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