divide 12 into 6 one side n balance it..# U& l) z' x! k( e1 V8 n
den take da heavier side which is 6 n divide into 2 parts again..0 g. B3 l- W, r3 }4 q
3 one side n another 3 another side..5.39.217.779 e n) B3 P! j- j$ {
den u take da heavier part again..! }; ]& n4 @+ t: L+ v) Q
now u left 3 pingpong.. u can simply choose 2 of it n balance again..5.39.217.77/ o" k: J, z$ T; E
if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan |
發表於 2008-5-20 11:28 AM
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