divide 12 into 6 one side n balance it..
c/ y+ ?2 a( `" V6 g4 F; I) A) `* vden take da heavier side which is 6 n divide into 2 parts again... k: J# M9 U6 ^( C; U2 `2 q7 H
3 one side n another 3 another side..5 a- f2 T$ k! S- k) F( E7 q
den u take da heavier part again..
! A; h3 z( o" }% _now u left 3 pingpong.. u can simply choose 2 of it n balance again..公仔箱論壇; @7 R5 e8 s) [% p
if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan |