take out 10 balls and 5 in each side
+ {9 q5 C' \- n. Q3 u6 J3 }& c( [if both side balance mean the other 2 balls one of them must be the heavy one then just take them to weight will find out which one is heavier.tvb now,tvbnow,bttvb9 @% H0 @& G/ @1 l7 c$ s& J
4 C* f' Q) [8 Q9 V' y4 C; n8 N8 w5.39.217.77if the heavy ball is inside the 10 balls, take out 4 balls from the heavier side which had 5 balls to weight 2 balls in each side.* b$ i: u3 z* c" S; H4 a l
if both side balance, which mean the one left is heavy one if not, just take the heavier side to weight will find out which one is the heaviest one.
# v1 Z4 H8 P3 K* S- \5 b1 ~5.39.217.77% D! Z! q( K& I, j" n
used less then 1 min to find out the answer.... |
發表於 2007-12-31 05:47 AM
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發表於 2008-1-1 08:48 AM
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