take out 10 balls and 5 in each side
3 g8 T$ r$ U) j$ r1 v! ytvb now,tvbnow,bttvbif both side balance mean the other 2 balls one of them must be the heavy one then just take them to weight will find out which one is heavier.
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if the heavy ball is inside the 10 balls, take out 4 balls from the heavier side which had 5 balls to weight 2 balls in each side.
. @1 _0 z9 R: g# J6 v/ p5.39.217.77if both side balance, which mean the one left is heavy one if not, just take the heavier side to weight will find out which one is the heaviest one.
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used less then 1 min to find out the answer.... |
發表於 2007-12-31 05:47 AM
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發表於 2008-1-1 08:48 AM
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