hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
2 r1 O8 Z  D/ J, _5.39.217.771st u divide the ball into two group (i group 6 ball)
2 s/ \  k% g& W$ Z) O/ MTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。then 称 them c which side is the heavy " t6 A8 B. ~, u
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
- o. J  O  k1 }: j2 Oif not balance take the heavy and then
( Y: w. Y& J& K( F4 q; btake the heavy group divided into 2 group i group contain 1 ball than 称 it
1 z6 z: Y1 k7 a, c% X8 u公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
& a! `2 v, z8 t6 B/ {% _tvb now,tvbnow,bttvb（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
" a& Z% ~) A/ a/ C0 x, ^tvb now,tvbnow,bttvb然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me