hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^公仔箱論壇- Z7 m+ u% R4 ], H( y, T
1st u divide the ball into two group (i group 6 ball); ]% G. b6 N( d' [/ Y
then 称 them c which side is the heavy tvb now,tvbnow,bttvb3 l4 X0 {6 S; b+ V4 f
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 6 r) D$ a( K, l
if not balance take the heavy and then
: g1 k4 n% s/ N1 I0 o5 V+ y( a5.39.217.77take the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb& Y. P% n! R% q! b% Y9 H
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇1 ~* E! @% J7 p7 T
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
" {  b2 `" ?, l5 t3 M  f5.39.217.77然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me