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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
7 F9 ~9 x1 Q& L+ j# x. c; U  c  ]1st u divide the ball into two group (i group 6 ball)公仔箱論壇3 l+ Q, @5 v6 p3 R0 b
then 称 them c which side is the heavy
4 Y" B# x- w7 P; U) e4 E公仔箱論壇then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group ! c3 m% _* H0 q! A" S& X/ M
if not balance take the heavy and then
( n/ [6 F& d( Z# L" p% p+ }2 p% m公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it
  l  g0 @6 _5 C* ?% j$ c7 W/ [tvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
. ^) b: m4 y& {' Y8 t3 Q+ C(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
8 m) a1 [) u  W. \公仔箱論壇然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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