hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
7 E/ C( A, Z- x* Otvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)5.39.217.77- h5 u6 L0 q5 b
then 称 them c which side is the heavy
  e& d# j' F$ R! Z, t1 e5.39.217.77then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group . _7 D# p$ _/ L) Z& M
if not balance take the heavy and then
& u; U2 V% o* M+ C+ t$ J; ltake the heavy group divided into 2 group i group contain 1 ball than 称 it
/ H8 \6 ^  O  H, b7 e% \TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 5 k9 F) G; u) I; s. Q6 [
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
/ G3 [* R7 r* M% X3 ^- ?5.39.217.77然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me