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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
; U  F$ v! E5 d+ @5 q, i7 Stvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)
' G8 E' p* ]) j! Uthen 称 them c which side is the heavy
8 Y5 G* C- @& l6 K8 ~then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 公仔箱論壇* T( t/ S4 k0 C8 S
if not balance take the heavy and then
! \8 H# e% C. C  ]; V/ t5.39.217.77take the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb. k# M# h! M3 E! u) E5 D
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: - F: Y/ ^. ]  }) k8 N/ w, p2 g
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边* }3 r2 u$ ^6 O& F
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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