hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb- m- w1 x( M0 z! f- W6 O* m0 S6 g( z
1st u divide the ball into two group (i group 6 ball)
4 j: f* |3 a! B1 mthen 称 them c which side is the heavy
/ i/ l! R6 y7 N! t" uthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
# h! L# k% `1 V+ f- R3 Lif not balance take the heavy and then
% [/ j% L: L! @" J- wtake the heavy group divided into 2 group i group contain 1 ball than 称 it
! n2 Z! d; N! h8 {- ^1 L/ z5.39.217.77than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 6 b8 N6 n/ d, |" N# M# q! Q2 ]
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
# l! E* R  c- x! S3 E: S3 i5.39.217.77然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me