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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
6 B( }3 a9 ?3 n& E" y1st u divide the ball into two group (i group 6 ball)公仔箱論壇1 e0 J! v& Y( g; D" q* v' B
then 称 them c which side is the heavy
/ Y0 _  @) Y7 r1 ttvb now,tvbnow,bttvbthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
/ j0 S& Y( Z+ Cif not balance take the heavy and then
+ N/ [8 s4 S' }+ x* X( jtake the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb8 W5 _; ^8 G* k( }3 ^
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 5.39.217.77' z8 ?: \/ o0 p1 B: L
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边tvb now,tvbnow,bttvb4 y& m& a% _% U& d3 j$ }* N+ ~
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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