That is a very simple mathematics question.
$ l0 I, S" B3 m r0 _公仔箱論壇Let x = Male, y = Female, z = Child5 F4 l; `9 R9 [: S2 m1 a$ F
6x + 3y + z/2 = 100 Formula 1
1 a" I- g' L$ u4 x: ] X公仔箱論壇x + y + z = 100 Formula 2
/ z4 M" ^ I: H2 s# x! zSimplify Formula 2 into z, we get z = 100 - x - y Formula 35 Z8 j" o$ U3 @* f% [' l1 c, O
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。7 b: B1 Z7 c& E- ]
Formula 4 can change into 11x + 5y = 100 Formula 5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% L, i4 l1 Q7 `0 \3 L( L% @
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇& B8 R. }9 @0 L
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb; a5 j$ }+ o! u- v+ R5 f
Eventually, the answer is 20 female and 80 children and no male. |