That is a very simple mathematics question.
! G+ U2 s! @: W/ }6 I' i+ e+ bTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child
3 v. i' ?- v7 _3 s( @$ etvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
7 B$ I' }* u% W9 Q% R- N9 Lx + y + z = 100 Formula 2tvb now,tvbnow,bttvb, N% j t+ l `# |% O
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇: R7 W: K X8 ~2 o7 I6 {
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4' d* g f) `7 d2 ^7 [9 n$ ~
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb' R5 r7 y; ?9 u) g& K
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.77, O! v, \& o, j4 {
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
3 u$ l4 X5 c) a; s$ c U3 p, _+ @Eventually, the answer is 20 female and 80 children and no male. |