That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。 \5 n# |4 o4 R$ Z/ |- A) w$ ]6 o& X
Let x = Male, y = Female, z = Childtvb now,tvbnow,bttvb$ Q2 `$ z% Z1 H; m; H; z
6x + 3y + z/2 = 100 Formula 1
7 N1 z. Q i& m9 q6 z. Gx + y + z = 100 Formula 2
3 b- V4 ]" F4 G0 q7 `! R: C, QSimplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb+ G; \' g% v: H
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
5 G% P% O; l5 [6 H2 d* x' R* bTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇) c! @- `. l0 Y; M5 d
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.777 G1 n- w5 ^* m) e: M9 T
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
9 }, {$ @7 E: _4 B/ W& ?. aTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |