That is a very simple mathematics question.
$ h: ^% i. |+ E$ [ `6 rTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 e0 l D/ ?) X7 b7 {" Q
6x + 3y + z/2 = 100 Formula 1
5 U. _/ ^# s; |. X' b3 e% G* s5.39.217.77x + y + z = 100 Formula 2
4 ]* h# U2 \$ G. f7 s1 N+ [5.39.217.77Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
+ W# d! |- S( XSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
, \' n% \, b, ]9 {2 W/ s7 N5.39.217.77Formula 4 can change into 11x + 5y = 100 Formula 5! ?! x9 C+ Z& g2 i
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.tvb now,tvbnow,bttvb4 d# W6 l5 K8 G! B
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb, n) g; j- q5 ?
Eventually, the answer is 20 female and 80 children and no male. |