That is a very simple mathematics question.
( @- b% d5 _! E( M( Q' z- h5 S% zLet x = Male, y = Female, z = Child9 t, c G# q+ E$ g
6x + 3y + z/2 = 100 Formula 1
2 i" X! Z3 W$ _2 E6 S3 @% M1 p" w3 e5.39.217.77x + y + z = 100 Formula 2, ^5 L$ G7 @8 B5 d: i1 z- ]
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
( n" E0 w8 ?/ O( {Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇; k9 N8 m* w& R
Formula 4 can change into 11x + 5y = 100 Formula 5
7 P% Q7 f! {* I% h$ n# n+ T0 ^7 u7 t6 n( mtvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want." C: o, H: e. ]. Z/ G$ N
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.+ r! h/ ]7 r! H2 C% R5 {
Eventually, the answer is 20 female and 80 children and no male. |