That is a very simple mathematics question.tvb now,tvbnow,bttvb' S$ R4 R6 L$ V5 M
Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。8 e5 u* x+ z# M1 t, S
6x + 3y + z/2 = 100 Formula 1公仔箱論壇& W! z7 G9 G( S- w4 ]
x + y + z = 100 Formula 2
+ O5 e/ A0 b6 k9 ASimplify Formula 2 into z, we get z = 100 - x - y Formula 3
$ L/ P( r: s' B! H$ f# K! H \2 NSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。( L! J; ~- L( _( W2 O0 q6 z
Formula 4 can change into 11x + 5y = 100 Formula 5
. T: I! y' N% X/ z+ U. n; a- u" MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
0 u! z4 g( h: z1 e: G5.39.217.77And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
2 u: P' N$ F' g. Z/ m9 ?5.39.217.77Eventually, the answer is 20 female and 80 children and no male. |