That is a very simple mathematics question.
9 b5 i( t5 u+ N% m0 v0 m7 b5.39.217.77Let x = Male, y = Female, z = Child公仔箱論壇% |3 \/ r/ `" ]1 a* M y% G3 [* S, a
6x + 3y + z/2 = 100 Formula 1
, b3 o1 p3 U ?& ETVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。x + y + z = 100 Formula 2公仔箱論壇1 v: g6 n& G, `( F3 |8 ?1 l ]
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
3 o6 J, B7 f) M5.39.217.77Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
$ g3 Y: p/ s8 ] W: Qtvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5
) P1 z- l. A2 K6 k: {In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.773 A4 Y) o( f+ m+ ~* H* q0 ?
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
) ~+ E/ s& p, E2 s0 YEventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:08 PM
| 
