That is a very simple mathematics question.
h& U4 |# k7 G+ s" {9 y5.39.217.77Let x = Male, y = Female, z = Child5.39.217.77! `6 y2 d, s: M7 q, ]
6x + 3y + z/2 = 100 Formula 1
; F1 S+ ?' T. y, p qtvb now,tvbnow,bttvbx + y + z = 100 Formula 2
& [* [5 X9 ~8 L K5.39.217.77Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
8 D" h+ I3 E' wtvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
; Q) x/ s, I Z @ D+ }$ FFormula 4 can change into 11x + 5y = 100 Formula 5
3 w" M5 _9 c* B. v! ^7 L+ z- X9 `' R( ytvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.tvb now,tvbnow,bttvb, M3 g% ~; @, A3 g- Y9 j
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇7 Q0 R: P1 n6 I# @& j. c: |
Eventually, the answer is 20 female and 80 children and no male. |