That is a very simple mathematics question.tvb now,tvbnow,bttvb( [3 g l+ Z) {9 Z0 M7 i6 j
Let x = Male, y = Female, z = Childtvb now,tvbnow,bttvb3 h; P+ m# Y% e3 j4 ~+ j% a: a- m
6x + 3y + z/2 = 100 Formula 1+ u; Z0 n3 w' R1 A0 n1 I
x + y + z = 100 Formula 2
3 q8 _# }; ]3 i$ Otvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
' C. K4 b/ w5 s, C. y1 q4 Rtvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
* u! q& h+ x2 U9 S) MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.77. H9 h! T# w6 `
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.779 R& q* b* I& R( z/ ^& N& Y" O0 V
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.77; e3 q T% f. E5 M& H: r) r
Eventually, the answer is 20 female and 80 children and no male. |