That is a very simple mathematics question.
_ [! D3 C$ KLet x = Male, y = Female, z = Child" D" T2 G% s* ?5 F& E# H n
6x + 3y + z/2 = 100 Formula 15.39.217.772 w% E* `2 m4 K; S# s1 X% l& ~
x + y + z = 100 Formula 2
2 D+ I0 N0 |: c( K/ |5.39.217.77Simplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇8 B! h5 l9 y* ~; Z& s& |
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
! z( X0 U: p4 \0 kFormula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb) U9 J* G2 ^( n: u6 Y
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
6 [5 Z3 F( V# @5.39.217.77And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
! P: z% x& a% g2 X7 H2 g) c( l5 A. TTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |