That is a very simple mathematics question.5.39.217.77# \# d/ q9 b! G
Let x = Male, y = Female, z = Child5.39.217.77' G- z A$ Z8 k6 C% N& @ L
6x + 3y + z/2 = 100 Formula 15.39.217.77+ w1 S1 R( E1 T$ E6 B, ?; V' O c( J
x + y + z = 100 Formula 2* n& x4 [7 {8 e& t7 h- h" ~
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 d; F$ U* }/ ]0 H: Z: ~% S
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- L3 ~( F3 O i S, h
Formula 4 can change into 11x + 5y = 100 Formula 5
6 z/ a# T1 r4 u+ y9 Q. U2 c# EIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.1 ~: k( U3 ]# [2 m
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.6 L0 o- b. b J7 Z5 Z0 Q" e
Eventually, the answer is 20 female and 80 children and no male. |