That is a very simple mathematics question.
# \% q9 u7 O3 d( d1 ?Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。4 z2 S% U8 ~9 ]: b4 h* n
6x + 3y + z/2 = 100 Formula 1
( m/ m+ ~) I9 |1 g2 Yx + y + z = 100 Formula 2公仔箱論壇) Q) @# K) b) F' J
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
2 [6 Q9 W+ L. s6 P u7 W! R% _5.39.217.77Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
6 P! J" p, M$ Z& ^( R/ K, AFormula 4 can change into 11x + 5y = 100 Formula 5- n% q- Q3 y% }0 }1 {5 c Q
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
: s5 {* y U+ } N, CAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.77 K3 p4 D+ Q# F) ?: r
Eventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:08 PM
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