That is a very simple mathematics question.
6 X1 q5 U% z- I1 I x: {! FTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child
# `9 u$ l1 f, L# b7 J |! R5.39.217.776x + 3y + z/2 = 100 Formula 1
6 C# u9 i+ c- n& n; n) `/ zx + y + z = 100 Formula 2
# d/ l- u; R) o9 B2 Ltvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
' a; F6 f: ?$ G3 N6 i: V$ b/ j( C/ ySub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
2 q9 d4 K# U1 q3 f; l3 o, D; E/ xTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5$ j6 N6 m8 @& d! K" P8 y
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.77+ |( u9 d. T/ @& i# l0 i! K
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
( f1 A/ g. X; z' n2 HTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:08 PM
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