That is a very simple mathematics question.7 i/ P8 [9 k7 z& G7 A
Let x = Male, y = Female, z = Child
9 ?) I& {$ G* j+ q5.39.217.776x + 3y + z/2 = 100 Formula 1+ e" X5 `. k7 f, Z1 ]: r( o
x + y + z = 100 Formula 2
/ ~- N) Z- c9 i( mTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
! a8 ~7 e! m5 m5.39.217.77Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4% B0 r$ h& ?3 @/ n
Formula 4 can change into 11x + 5y = 100 Formula 5
) S4 }/ x" b2 T4 Y" sIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.3 s' J5 e \# N; ~
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
8 {2 a, K+ \. O3 x3 a6 bEventually, the answer is 20 female and 80 children and no male. |