That is a very simple mathematics question.5.39.217.77) i) M) a" s- z$ _$ f G6 B. [9 \
Let x = Male, y = Female, z = Child公仔箱論壇. E( {# C/ k- l( P$ ?" _6 i
6x + 3y + z/2 = 100 Formula 1
3 }7 ^0 y) J. y4 \6 Sx + y + z = 100 Formula 2
" N( M$ X1 e' m7 y$ }3 P: v% k+ eSimplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.77, ]6 o# `: Y/ L0 i$ ?# X
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4; O! G9 X* x/ f& | m
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb: d, D( \ f- n6 N
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.4 S) `6 c* s) v; |
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
# I; O6 h. N( ]' U7 b& z8 n5.39.217.77Eventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:08 PM
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