That is a very simple mathematics question.5.39.217.77. g2 u: Q' |! `+ _5 q
Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% b# s% Y) y1 x$ A1 |
6x + 3y + z/2 = 100 Formula 1
* S* j& e7 {2 m; d5 w3 @1 K" stvb now,tvbnow,bttvbx + y + z = 100 Formula 2" k" \& V5 q& C- m" F
Simplify Formula 2 into z, we get z = 100 - x - y Formula 36 `* O. b( }9 \2 F
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
3 B# m$ A& l7 j# TFormula 4 can change into 11x + 5y = 100 Formula 5
0 d ` e' t5 E7 }/ V" }! Stvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- D) E/ S$ J, S7 o. U; L
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.! c. _$ ]( _3 V+ H5 n" I4 h2 |
Eventually, the answer is 20 female and 80 children and no male. |